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maui044
Level: Baguhan
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How do you compute for the shortest distance bet 2 parallel lines, say for example, 2x - 3y = 6 and 2x - 3y = -4?

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eksaktosx
from x-y axis,taking 3 pts.(x,y) and using (z^2=x^2+y^2);
then half of "z" value.result is ((325)^1/2)/6
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anu-ano
base=3-1/3; height=5
tan@=base/height; @=33.663 deg
sin@=sd/x ;(sd=shortest dist.)&(x=height as new hypotenuse.
sd=sin(33.663deg)*5
sd=2.77
or; sd=sin(56.336deg)*y ;(y=3-1/3,as new hypotenuse);
sd=sin(56.336)*10/3
sd=2.77
0 : 0 | 0% AC


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